Q:

Will someone please help me!!! I don’t know the answer to these! I don’t even know if I did them right!

Accepted Solution

A:
Answer:[tex]BD = 12[/tex] units[tex]AB = 16[/tex] units[tex]FG=\sqrt{105}[/tex][tex]EC=4\sqrt{10}[/tex] units[tex]AC=8\sqrt{10}[/tex] unitsStep-by-step explanation:A circumcenter is the point  where the perpendicular bisectors of a triangle intersect. This means BD = DC;BF = FA;AE = EC.Since BC = 24 units, then BD = 12 units (half of BC).Since FA = 8 units, AB = 16 units (twice FA).Consider right triangle BGF. In this triangle, BF = 8 units (congruent to FA), BG = 13 units. By the Pythagorean theorem,[tex]FG^2=BG^2-BF^2\\ \\FG^2=13^2-8^2\\ \\FG^2=169-64=105\\ \\FG=\sqrt{105}\ units[/tex] Triangles BFG and AFG are congruent right triangles, then BG = AG. In right triangle AGE, [tex]GE=3[/tex] units, [tex]AG=13[/tex] units. By the Pythagorean theorem,[tex]AE^2=AG^2-GE^2\\ \\AE^2=13^2-3^2=169-9=160\\ \\AE=\sqrt{160}=4\sqrt{10}\ units[/tex][tex]AE = EC=4\sqrt{10}\ units[/tex][tex]AC = 2AE=2\cdot 4\sqrt{10}=8\sqrt{10}\ units[/tex]