You just got a free ticket for a boat ride, and you can bring along 3 friends! Unfortunately, you have 6 friends who want to come along.How many different groups of friends could you take with you?

Answer:Assuming that your own ticket is already secured.From the 5 friends you can only choose 3.The order in which these friends are chosen is not relevant. So this is a Combination problem.Where the order is relevant the problem becomes a Permutation problem! So the answer is 5 combination 3.          =  ⁵C₃⁵C₃  =  (5 * 4 * 3) / ( 3 * 2 * 1) = 20You can take 10 groups of any 3 of your 6 friends.Hope this helps! have a spooky day!Brainly?